Combinatorial Game Theory
who wins, and by how much
Series

Reversibility — the series

5 essays on one idea, from the one that introduces it to the one that assumes the rest.
  1. The reduction that puts options back. How the two reductions change the width of a form. Domination only ever removes an option. Bypassing a reversible option substitutes the answer's whole option list, so it can leave the form wider than it started — and the finished canonical form can be wider than the form it came from.

    The reduction that puts options back

    Canonical form is presented as simplification, and half of it is. Deleting a dominated option takes one away. Bypassing a reversible one substitutes the answer's whole option list, so it can leave the form wider than it started — and 60 of 32,428 forms end up with a canonical form wider than they are.

    part 1 · values
  2. How many options a value needs. The canonical form is the smallest form of its value, so the number of options it carries is a property of the value. Three days of the construction, with the widths that occur and the widest value of each.

    How wide a form can get

    Bypassing a reversible option replaces it with a whole option list, so a form grows in the middle of its own reduction. Whether it can come out wider than it went in is the question that leaves standing, and over 64,515 forms built from day-two options the answer is no, not once — the growth is real, it is transient, and the widest canonical form reached is exactly as wide as the widest form that reaches it.

    part 2 · values
  3. What a value costs to write down. Every one of the 1,474 values born by day three, grouped by the width of its canonical form, with the number of symbols the form takes when it is written out. Each count was obtained by walking the canonical form and counting its nodes, so a subposition appearing twice is counted twice — which is what writing it out does. The widest values of the day are not the longest to write.

    What a value costs to write down

    The canonical form is the smallest form of its value, and it is smallest in the one currency the reduction happens to spend: options. Counted in symbols it is nothing of the kind — the widest value born by day three is not the longest, the longest has six options rather than seven, and every canonical form on the day except the seven integers writes some position out twice.

    part 3 · values
  4. What a day of canonical forms costs, written out and written once. Three costs for the values born by each of the first three days: every node written every time it occurs, every distinct subposition of a single form, and every distinct subposition of any form of the day. The last is one node per value, and the gap between the first and the last widens as the construction goes on.

    The same position, written once

    Writing out the canonical forms of day three takes 24,940 nodes. Naming each distinct subposition once inside each form takes 10,102, and naming each distinct subposition once across the whole day takes exactly 1,474 — one per value, because nothing appears inside a canonical form that is not itself a value of the day.

    part 4 · values
  5. The same game, written twice. A position as it arises and the same position reduced. Left would never move to 0 when 2 is available, so that option is dominated and can go. The two games are equal — checked, not assumed — and the second is the canonical form.

    A reduction that reads a graph

    The two reductions are defined as deletions from an option list, and the shared form has no option lists — a node is reached from several parents at once. Both restate as rewritings at a node, the rewriting is confluent, and its fixed point is the canonical form. What does not carry over is the sharing: four fifths of the shared nodes need a different answer under different parents.

    part 5 · values

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