Domineering on 3×4 — and who wins
A Domineering board with the outcome stated before anybody moves. Left places vertically, Right horizontally, and on this board Right wins whoever starts. Every reply the machine can make was worked out in advance from the game recursion, so it is following the analysis rather than searching.
3 essays call
play-domineering. The drawing above is what it returns with no arguments at all; every
call below passes it something, because a placement that passes nothing draws whichever
member of the family the generator happens to default to rather than the one its essay argues
about.
The positions it draws
1 distinct position, harvested by running this generator again at the options each essay passed it.
| Position | Worth | Outcome | Drawn in |
|---|---|---|---|
3×4 |
−3/2 |
R | A board that is a sum of its regions · "Left wins" has no short proof · Domineering · A position reached eleven ways is one position · The values of every small board · Which shapes are worth fighting over |
It plays back
The winner is named before a move is made, and every reply was worked out in advance.
-
"Left wins" has no short proof — Domineering on 3×4 — and who wins,
worth
−3/2, R, 20 positions solved before the page was served. -
A position reached eleven ways is one position — Domineering on 3×4 — and who wins,
worth
−3/2, R, 20 positions solved before the page was served. -
Domineering — Domineering on 3×4 — and who wins,
worth
−3/2, R, 20 positions solved before the page was served.
Where it is called
Changing this generator changes every one of these figures.
Domineering
One player places dominoes vertically, the other horizontally, on a shared grid. The rules take one line, the values are a mess, and that mess is the point — this is what the theory looks like applied to a game nobody designed for it.
A position reached eleven ways is one position
A 4×4 Domineering board has 5,700 positions in it and 6,257,129 routes through them. Three heaps of 7, 11 and 13 have 480 positions and 7.6 × 10¹⁶ routes. The gap between those two numbers is not an optimisation — it is the difference between a search that finishes and one that does not.
"Left wins" has no short proof
A complete solution of Nim on heaps of 7, 11 and 13 is 480 table entries. A winning strategy for the same position — one move of the winner's at each of their turns, and an answer to every reply — has 56,167,022 nodes in it. The answer is smaller than the proof by a factor of a hundred thousand.
The whole library · The position index · The figures that play back